RMweb Premium newbryford Posted May 10, 2012 RMweb Premium Share Posted May 10, 2012 And if i remember correctly v=u+at Cheers, Mick Link to post Share on other sites More sharing options...
bertiedog Posted May 10, 2012 Share Posted May 10, 2012 And if i remember correctly v=u+at Cheers, Mick From this formula we can derive the velocity, if we know the acceleration,time and initial velocity, but it still can't predict when a train will arrive...........does the V stand for Virgin............oh dear........ Link to post Share on other sites More sharing options...
RMweb Gold Colin_McLeod Posted May 10, 2012 RMweb Gold Share Posted May 10, 2012 . Link to post Share on other sites More sharing options...
bertiedog Posted May 10, 2012 Share Posted May 10, 2012 Try you tube: http://youtu.be/Bfq5kju627c From a Ma and Pa kettle film, classic maths!! Stephen Link to post Share on other sites More sharing options...
Michael Delamar Posted May 11, 2012 Share Posted May 11, 2012 10001110101101001010001000001001010010001011110010101010100101010102 Link to post Share on other sites More sharing options...
RMweb Premium Physicsman Posted May 11, 2012 RMweb Premium Share Posted May 11, 2012 Turning the clock back a bit... L + L = C Makes sense, doesn't it? Jeff Link to post Share on other sites More sharing options...
RMweb Gold beast66606 Posted May 11, 2012 RMweb Gold Share Posted May 11, 2012 Link to post Share on other sites More sharing options...
RMweb Gold Colin_McLeod Posted May 11, 2012 RMweb Gold Share Posted May 11, 2012 II times I is II II times II is IV II times III is VI II times IV is VIII II times V is X II times VI is XII II times VII is XIV II times VIII is XVI II times IX is XVIII II times X is XX The square root of XLIX is VII Anyone for long division in Roman Numerals? Link to post Share on other sites More sharing options...
RMweb Premium Physicsman Posted May 11, 2012 RMweb Premium Share Posted May 11, 2012 Blimey, beast! Have you been reading "My first Sums book" during the night? Having said that, with the progress that Chinese children are making, they probably learn integration and binomial expansions before the age of 5. Jeff Link to post Share on other sites More sharing options...
RMweb Gold beast66606 Posted May 11, 2012 RMweb Gold Share Posted May 11, 2012 II times I is II II times II is IV II times III is VI II times IV is VIII II times V is X II times VI is XII II times VII is XIV II times VIII is XVI II times IX is XVIII II times X is XX The square root of XLIX is VII Anyone for long division in Roman Numerals? SPQR Link to post Share on other sites More sharing options...
RMweb Gold martin_wynne Posted May 11, 2012 Author RMweb Gold Share Posted May 11, 2012 The square root of XLIX is VII The square root of ....- ----. is --... Link to post Share on other sites More sharing options...
RMweb Premium Physicsman Posted May 11, 2012 RMweb Premium Share Posted May 11, 2012 Martin, do you mean as in... The square root of - XLIX = 7I or should that be VII I ? To the casual onlooker this thread must look totally crazy!! Jeff Link to post Share on other sites More sharing options...
Thomas Posted May 11, 2012 Share Posted May 11, 2012 1CO-CO1 Link to post Share on other sites More sharing options...
RMweb Premium Grafarman Posted May 11, 2012 RMweb Premium Share Posted May 11, 2012 1CO-CO1 I'll see your 1CO-CO1 and raise you 2-8-8-2... Link to post Share on other sites More sharing options...
PLD Posted May 11, 2012 Share Posted May 11, 2012 2-6-2+2-6-2=NGG16 0-4-0+0-4-0=K1 Link to post Share on other sites More sharing options...
Thomas Posted May 11, 2012 Share Posted May 11, 2012 2-C+C-2 =PRR GG1 AAR rules apply Link to post Share on other sites More sharing options...
Michael Delamar Posted May 11, 2012 Share Posted May 11, 2012 Link to post Share on other sites More sharing options...
RMweb Gold SHMD Posted May 11, 2012 RMweb Gold Share Posted May 11, 2012 Doing “Long Division†with Roman Numerals was taught at degree level during the “Empireâ€. It involved using anything to hand and having the skill to manipulate it all, again, by hand. (Scratch building.) Later new techniques and tools come in and “Long Division†became easier. You still do things by hand but all the bits are broken down into easily manageable parts, which must still be assembled in the correct order. (Kit building.) Now, calculators and computers do the, (any), division for you. (RTR!) But you still have to apply the answer correctly, or even put the relevant numbers in in the first place! 22/7=3rem1 1*10=10 10/7=1rem3 3*10=30 30/7=4rem2 2*10=20 20/7=2rem6 6*10=60 60/7=8rem4 4*10=40 40/7=5rem5 5*10=50 50/7=7rem1 1*10=10 10/7=1rem3 3*10=30 30/7=4rem2 Now taking the 1st digit BEFORE the “rem's†and putting a decimal point just after the 1st digit you get:- 3.14285714 3.14159267 was my original answer in post #3, giving an error of %4.02331364002. (OK, I cheated and used a RTR calculator here.) Close enough for me who has been know to use 3 and a bit in real life!!! I know there are enough members, on here, who have used 22/7. Thus, when it comes to mathematics, I am kit building the answers! Kev. For more details see thread:- http://www.rmweb.co....ilding-in-2012/ Link to post Share on other sites More sharing options...
kintbury jon Posted May 11, 2012 Share Posted May 11, 2012 This question has appeared in an Abingdon Scholarship paper - I think it's great though don't know how many kids aged 13 would know where to start. Part a is alright, part b a little harder! a) Prove that N = 6^1 + 6^4 + 6^9 + 6^16 + . . . + 6^81 + 6^100 is divisible by 2, 3 and 5. b ) By looking at powers of 6 quite carefully, can you decide whether N is divisible by 7? Link to post Share on other sites More sharing options...
RMweb Gold SHMD Posted May 11, 2012 RMweb Gold Share Posted May 11, 2012 Err. Sir, sorry sir. Cant you repeat that please. N = what 6 to the power … 1 er... 1 to the power 1, er.. power 2, power 3. etcetera. Sir. Sorry Sir. Errrrr..........er.....er.... So 1 + 1 = 2? Link to post Share on other sites More sharing options...
Jamie Posted May 11, 2012 Share Posted May 11, 2012 ... Prove that ... The two words in an exam question that meant I was never, ever going to reach the desired answer. Link to post Share on other sites More sharing options...
RMweb Gold beast66606 Posted May 11, 2012 RMweb Gold Share Posted May 11, 2012 The two words in an exam question that meant I was never, ever going to reach the desired answer. QED Link to post Share on other sites More sharing options...
RMweb Premium Grafarman Posted May 11, 2012 RMweb Premium Share Posted May 11, 2012 Qi...? Link to post Share on other sites More sharing options...
eastwestdivide Posted May 11, 2012 Share Posted May 11, 2012 Our maths teacher had something against Latin, so instead of QED, he used to use "W to the 5th" = Which Was What Was Wanted. Link to post Share on other sites More sharing options...
Mike G Posted May 11, 2012 Share Posted May 11, 2012 "Your logic is undeniable"....Spock Link to post Share on other sites More sharing options...
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